Integer overflow error java

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5 andĬasting with (int) using formulas like the following. Values of type double can be rounded to the nearest integer by adding or subtracting. If you have integers and you want a double result from some mathematical operation cast one of the integers to a double using (double) as shown above.

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If there is at least one double in the operation, Java will widen the type of the other operand to double too and return the result in a double. But, if you use a mixture of integers (int) and decimal (double) numbers Java will assume that you want a double result. Java assumes that if you are doing division with integers that you want an integer result and it will truncate and throw away the part after the decimal point. Public class RunestoneTests extends void testMain() throws IOException What happens when you divide an int by an int or with a double operand or with the type cast (double) on one of the operands?

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